Reply to comment

Karina Granadeno

Fly Traits:

 

F1 Generation (+) is all wild type trait. (3 to 1 ratio of wild VS Ebony/ degree of freedom)

F2 Ebony (E) type trait.

Original parents (P)

Variation with one element for both parents.

Each gene in two different states with parents giving one copy from each parent. Every individual has two versions of a gene.

Phenotype –Appearance

Genotype – Actual genes present

++ = Homozygous (SAME)

+E = Heterozygous (DIFFERENT)

RESULTS:

1.)    Monohybrid Cross:

2.)    Dihybrid Cross:

 

Dihybrid Cross: ++, VGVG, EE, VGE

ORIGINAL PARENTS Female Fly: Wild Type (+)

ORIGINAL PARENTS Male Fly: Spineless Type (SS)

Female: + 494

Male: + 482

Female: +369

Female: SS 123

Male: +364

Male: SS 111

 

ORIGINAL PARENT: Female Fly: Wild Type (+)

ORIGINAL PARENT: Male Black: Wild Type(+); PR (PURPLE) Eyes; BL (Black Body)

F1

Female: + 508

Male: +484

F2

Female + 376; PR 12, BL 9; PRBL 97

Male + 360; PR 9; BL 8; PRBL 111

 

Conclusions: We have discovered that for the F1 generation using original parents that carry a wild type and a single variance such as spineless create the 3 to 1 ratio in their offspring. But when the original parent (single) has two variances such as eye color and wing type you receive the 2 to 2 ratio. Our problem with the third experiment was when both parents had two different variances it still generated the 2 to 2 ratio. This third experiment suggests that the trait variances are significant and will dictate the offspring ratio. So it’s not that Mendel’s trait formula of 3 to 1 and 9 to 3 are wrong it’s that it only applies to specific traits that are possibly dominant. You would need to test all flies in order to come to a definite conclusion.

We also ran other experiments and concluded that some crossings are not possible.